By Ivan Rival (ed.)

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If we parallel-translate the subspace W through a fixed vector v0 in +1 \ W, obtaining v0 + W— + W}, then each 1-subspace in '\ Wmeets v0 + Win exactly one point. This sets up a 1:1 onto correspondence between the points of '(k) and the points of k"; Figure 2 indicates a typical situation for Ic = II, n = 2. 7. finlty P' Any affine n-space may be regarded as the afilne part of a P'(k) relative to some 1(k) by taking a parallel translate of an n-dimensional subspace W 1, and identifying each point P of this parallel translate with the 1of subspace ofk'41 through P.

Dehomogenizing at X = 0 yields Figure 1 ib; the original line at 43 lI:Plmne curves z z L, x y (b) (c) Figure 11 infinity is the great circle corresponding to Z = 0, which appears as the Yaxis in Figure Jib; the n lines intersect the Y-axis at the origin with multiplicity n. plane appears as a distinct line through the origin in the (Y, Z)-plane, so again will intersect the n lines in one point with multiplicity n. -(Y — n) is n, Bézout's since the degree of p(X, Y) = (Y — the n complex projective lines theorem tells us that in the extension to intersect any other line in n points, counted with multiplicity.

8 (Two basic integral theorems). Let f(X) be a function analytic at each point of an open set containing a closed disk in C with boundary and suppose that within A = A\t3A there are exactly N zeros of f(X), counted with multiplicity. 6. That the zero-set of p(X, Y) near (0,0) forms the çb(X) will follow easily from the argument principle; it will then be our task to prove that is analytic. To show the zero-set forms a graph, we first note that the definition of multiplicity of a zero shows that the hypotheses p(O, 0) = 0 and PI4O, 0) 0 together form a way of expressing that the polynomial $0, Y) E C(Y) has Y = 0 as a zero of multiplicity 1.